(x^3+4x^2-9x-36)/(x-3)

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Solution for (x^3+4x^2-9x-36)/(x-3) equation: 


D( x )

x-3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:3) U (3:+oo)

(x^3+4*x^2-(9*x)-36)/(x-3) = 0

(x^3+4*x^2-9*x-36)/(x-3) = 0

x^3+4*x^2-9*x-36 = 0

x^3+4*x^2-9*x-36

x^2*(x+4)-9*x-36

x^2*(x+4)-9*(x+4)

(x^2-9)*(x+4)

((x^2-9)*(x+4))/(x-3) = 0

( x+4 )

x+4 = 0 // - 4

x = -4

( x^2-9 )

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in { 3} 

x in { -4, -3 }

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